??? 07/14/09 15:26 Modified: 07/14/09 15:33 Read: times |
#167272 - Solder it on the solder side! Responding to: ???'s previous message |
Sivanand said:
IS the one In4148 already inside the relay not suffcient? There's no 1N4148! There's series circuit of 1N4148 and 56V zener, iy you can trust the datasheet! This will very probably destroy the LEDs, because they aren't designed to withstand such a high reverse voltage. Ok, Sivanand, let me explain how a free wheeling diode is working. Imagine the following brain experiment: If you connect pin 3 of your relay to 0V, while having pin 2 connected to 5V, then a current is flowing through the relay. This will generate a strong magnetic field within the coil of relay. If you now abruptely disconnect pin 3 of relay from 0V, the magnetic field is collapsing and by this producing a high voltage across pin 2 and pin 3 of relay, the so called inductive kick. As pin 2 is still connected to 5V, at pin 3 (which is disconnected now from the rest of world) a voltage can be measured which is many many volts more positive than +5V. You can easily measure hundreds of volt here. The idea of this free wheeling diode is now to limit this voltage at pin 3 of relay to 5.7V. Why exactly 5.7V? Just one diode voltage drop more than 5V. But datasheet says that a zener is here connected to the relay, which allows a voltage of about 56V across the relay coil. If this is true, then the LEDs will see a too high reverse voltage and are in risk to be damaged. Kai |