Your circuit eliminates switch bounce when pushed.

But what happens when it is released? The clock node is floating. Eventually, the node will discharge do the input trip point. There, the presence of noise may clock your flop many times.

You get a good clock on pressing the button on, and you get N number of clocks some time later when the button is released.

You might get lucky, and have N=0. And then later on, when you are showing your circuit to someone important, N may be equal to 7.

A 10K resistor to the switch, and a new, 160k resistor across the capacitor might work. It depends on how bouncy your switch is.

There are more elegant solutions. But I'll let the others tell you them.