??? 03/11/07 17:16 Read: times |
#134717 - Not for Application. Just learning. Responding to: ???'s previous message |
Kai said:
It looks a bit strange. So, to finally decide whether your circuit is good or not, we need to know a bit more about your application! The circuit is not intended for any particular application. As of now, i was going through the book and were discussing with you for any clarifications needed. As far as this instrumentation Amplifier circuit is concerned, i read about it and thought of designing a circuit that could amplify an input voltage range of (0 to 10)mV according to the gain i have specified in the description of the circuit. So i though of knowing how better i have aproached to the need of amplifying (0 to 10)mV to the gain i have specified in the description. Here is the description: Description of the circuit: - U2A and U3A are used as high resistance buffer to prevent loading the signal source heavily ( By 'loading the signal source' i assume drawing high current from the input source V1 and V2) - The circuit is designed to amplify the input voltage of range (0 to 10)mV into 500 times. - The high resistance buffer stage gives a gain of 5 (when R5 set to 1K), when V1 not equal to V2. The difference between these two buffer outputs is amplified 100 times by the differential stage U4A. - When V1 = V2, The high resistance buffer stage acts as a voltage follower.(But not sure of how that happens) Kindly let me know for any details you may require. regard's Suresh. |