??? 02/18/06 11:21 Read: times |
#110268 - other way 'round Responding to: ???'s previous message |
I think you are confused a bit...
The "current peak" at cca 2V is the current supplied from the pin the port has been set to "1" and some external device attempts to pull it down. When you set the port to "0" it simply sinks the current as per your list item 1. Only this is relevant for connecting PNP transistor (base). Jan Waclawek |
Topic | Author | Date |
AT89s52 Port pin clarifications: | 01/01/70 00:00 | |
nice copy, where is the question | 01/01/70 00:00 | |
output characteristics | 01/01/70 00:00 | |
most confusing post | 01/01/70 00:00 | |
Answers | 01/01/70 00:00 | |
Logic 1 to 0 transition | 01/01/70 00:00 | |
You haven't read the 'bible' chapter... | 01/01/70 00:00 | |
no details about transition from logic 1 | 01/01/70 00:00 | |
other way 'round | 01/01/70 00:00 | |
There ARE!! | 01/01/70 00:00 | |
pFET2 | 01/01/70 00:00 | |
Weak and very weak pull-ups | 01/01/70 00:00 | |
maintaining low source impedence? | 01/01/70 00:00 | |
by making thje driver a sink............ | 01/01/70 00:00 | |
Pull-downs create problems | 01/01/70 00:00 | |
Maximum IOL per port pin: 10 mA ? | 01/01/70 00:00 | |
IOL | 01/01/70 00:00 | |
IOL = 10mA or 1.6mA? in port 1 | 01/01/70 00:00 | |
Depends on load | 01/01/70 00:00 |