??? 12/22/09 14:45 Modified: 12/22/09 14:46 Read: times |
#171854 - re:ADUC816 Responding to: ???'s previous message |
Stephen,
Nyquist's theorem states that the minimum frequency to reconstruct a signal is twice that of the signal of interest. The minimum would be to sample at twice the frequency of the signal coming in. Set the SF SFR to 1, that will give you a sampling frequency of ~ 1300 Hz. At 105 Hz sampling frequency, you can barely sample a 50 Hz signal. |
Topic | Author | Date |
ADuC816 Problem | 01/01/70 00:00 | |
Sample rate ? | 01/01/70 00:00 | |
Isn't that exactly what you should get? | 01/01/70 00:00 | |
Indeed! | 01/01/70 00:00 | |
Hmm | 01/01/70 00:00 | |
average of the repetitive peak ? | 01/01/70 00:00 | |
Better | 01/01/70 00:00 | |
Clarification | 01/01/70 00:00 | |
Signal Frequency | 01/01/70 00:00 | |
magnitude | 01/01/70 00:00 | |
Dump a number of samples to check | 01/01/70 00:00 | |
it is possible? | 01/01/70 00:00 | |
fast sample-and-hold | 01/01/70 00:00 | |
sorry, but | 01/01/70 00:00 | |
and | 01/01/70 00:00 | |
it won't | 01/01/70 00:00 | |
Undersampling often quite powerful | 01/01/70 00:00 | |
what is conclusion for OP? | 01/01/70 00:00 | |
How about precision rectification? | 01/01/70 00:00 | |
re:ADUC816 | 01/01/70 00:00 | |
sure, you can | 01/01/70 00:00 | |
Most cheaper digital scopes uses repetitive sampling | 01/01/70 00:00 | |
how about | 01/01/70 00:00 | |
SF=1 | 01/01/70 00:00 | |
Consistent not a simple subset of accurate | 01/01/70 00:00 | |
Dumping Values | 01/01/70 00:00 | |
*EDIT* | 01/01/70 00:00 | |
Circuit![]() | 01/01/70 00:00 |