??? 04/30/10 14:15 Modified: 04/30/10 14:18 Read: times Msg Score: +1 +1 Good Answer/Helpful |
#175551 - 600W, how to calculate? Responding to: ???'s previous message |
Dear Ap,
as I told earlier, the frequency distribution of music shows, that the content of high frequency power is very low. In the following plot you see the power distribution versus frequency by which loudspeakers are tested and rated: Interpret it as follows: If the power over the whole bandwidth is 100%, then a loudspeaker (chassis) must take 20% of this power during a speaker testing, when it radiates all the frequencies above 500Hz. Above about 2kHz is will be only 2%. So, if you take a tweeter, put it behind a steep high pass filter with a corner frequency of 2kHz, then it has to withstand only 2% of the whole power during the speaker testing. Or by other words, if this speaker can actually withstand 1W thermically, then you can have this tweeter part of a loudspeaker system rated at 50W, because 2% of 50W is 1W. This 600W rating of your tweeter calculates in the same way: Take a much higher corner frequency of let's say 6kHz, look at the plot, how much power the speaker test signal then contains (nearly zero!) and make the same calculation as above. No 600W tweeter can withstand 600W actually, but you can combine it with a 600W loudspeaker system, if you take a steep high pass filter (usually >18dB/Oct) and a high corner frequency (usually >5kHz). It will at least withstand the loudspeaker test signal... Kai Klaas |