Not having read the bible or anything else for this particular instruction, my assumption when I first encountered it, was it would mean:

JMP @A+DPTR ;take the value at (A+DPTR) and jump to that address.

But apparently it means:

JMP @A+DPTR ;jump to the address (A+DPTR)

So I expected an indirection because of the @, but there isn't any.

Jan, your version would mean to me:

JMP (@A) + DPTR ;get the value at the address stored at A (in which memory?), add it to DPTR and jump to it.

Had I written the assembly instruction set, I would probably have coded it as:

LJMP A+DPTR

As for the jumptable, it could of course also have 3 byte elements and you can fill it with LJMP instructions. It just takes a tiny bit more calculation on A and of course a smaller maximum number of items.

Maarten