| ??? 05/05/06 15:54 Read: times |
#115682 - the role of RL and C Responding to: ???'s previous message |
In your circuit RL and C define the frequncy response in the frequency domain but in the S domain the define the positions of the poles and zeros in the transfer function.The two are equivelent, as you can see here;-
http://www.chem.mtu.edu/~tbco/cm416/TFBODE.html However once you have relised that the values of RL and C define the frequency response, and the pole positions you can then simplfy the transfer functions for example a first order low pass filter has a transfer function of the form 1/( S^2+(wt)) where t is the time constant formed by the passive components. |
| Topic | Author | Date |
| PhD Qualifier | 01/01/70 00:00 | |
| Study resonance | 01/01/70 00:00 | |
| RLC Circuits | 01/01/70 00:00 | |
| And that's all you're getting | 01/01/70 00:00 | |
| Well | 01/01/70 00:00 | |
| Maths | 01/01/70 00:00 | |
| Maths | 01/01/70 00:00 | |
| Simplify ! | 01/01/70 00:00 | |
| Eh | 01/01/70 00:00 | |
| Ancient books | 01/01/70 00:00 | |
| books | 01/01/70 00:00 | |
| the role of RL and C | 01/01/70 00:00 | |
| Stay with 1/Z | 01/01/70 00:00 | |
| Well | 01/01/70 00:00 | |
| ... and at resonance | 01/01/70 00:00 | |
| Vector-diagram | 01/01/70 00:00 | |
| phasor | 01/01/70 00:00 | |
Thanks! | 01/01/70 00:00 |