| ??? 12/25/06 17:05 Modified: 12/25/06 17:27 Read: times |
#130103 - Why not measuring voltage drop across load? Responding to: ???'s previous message |
Alireza said:
In summery, excitation voltage is applied on the load and current will be read, then current waveform will be multiplied separately to two different waveforms which have been synchronized with excitation waveform and one has 90 degree phase shift relative to the other. In this way real and imaginary parts of impedance will be calculated. Why that complicated? Why not applying the excitation voltage to a series circuit of suited ohmic resistance (shunt) and load, and then measuring the voltage drops across shunt and load? This would give you the impedance and the phase. By the way, what is the equivalent circuit model of your load? Capacitance in parallel to ohmic resistance? Or do you measure surface resistivity? By the help of Van der Pauw methode? Kai |
