| ??? 05/20/12 01:10 Read: times |
#187437 - a= 2/s x v^2 Responding to: ???'s previous message |
So, the more "s" you allow the carriage to reach velocitiy "v", the less acceleration "a" will you need.
Kai Klaas |
| Topic | Author | Date |
| Production Line Velocity Calculation | 01/01/70 00:00 | |
| are you saying | 01/01/70 00:00 | |
| Yes, | 01/01/70 00:00 | |
| Acceleration | 01/01/70 00:00 | |
| thanks | 01/01/70 00:00 | |
| a= 2/s x v^2 | 01/01/70 00:00 | |
| Hi,Kai | 01/01/70 00:00 | |
| true | 01/01/70 00:00 | |
| Need Coordinated Motion Profile | 01/01/70 00:00 | |
| The Industry Terminology,,, | 01/01/70 00:00 | |
| maybe | 01/01/70 00:00 | |
| Another way | 01/01/70 00:00 | |
maybe NOT | 01/01/70 00:00 |