| ??? 02/27/07 15:35 Modified: 02/27/07 15:51 Read: times |
#133826 - Now it is clearer... Responding to: ???'s previous message |
Kai said:
To be honestly, by intuition I still can't believe that two inverters shall be enough to invert three signals... Because I always looked on the signals as three independent things. Means, if the circuitry which is to invert !A, for instance, does not see any other signal, then indeed three inverters are needed. But, here the situation looks totally different: The circuitry to invert !A at the same time sees signals B and C. And by this (except for A=B=C="0", which is handled differently) there's always a "1", when B="1" or C="1", which can be used to fabricate the !A="1". The function of the help signals then is only to let pass a suited "1" from B or C to the output !A, but not to invert each individual input signal! And so two inverters can be really enough to fabricate the three "1". Kai |
| Topic | Author | Date |
| weekend brainteaser | 01/01/70 00:00 | |
| here goes my weekend. | 01/01/70 00:00 | |
| Dont worry once you see the answer its obvious. | 01/01/70 00:00 | |
| Logically thinking... | 01/01/70 00:00 | |
| you are quite close | 01/01/70 00:00 | |
| One solution... | 01/01/70 00:00 | |
| yey we have a winner | 01/01/70 00:00 | |
| Very Nice | 01/01/70 00:00 | |
| Thanks | 01/01/70 00:00 | |
| An Alternate Solution | 01/01/70 00:00 | |
| Yes... | 01/01/70 00:00 | |
Ive run out ;-( | 01/01/70 00:00 | |
| Congratulations, Kai! | 01/01/70 00:00 | |
| Thanks | 01/01/70 00:00 | |
| Now it is clearer... | 01/01/70 00:00 |