| ??? 02/26/07 05:11 Modified: 02/26/07 05:16 Read: times |
#133683 - Thanks Responding to: ???'s previous message |
Russ said:
I fiddled with the problem for a couple of hours and never got my thinking far enough "out of the box" to do any good. At the beginning it was hard for me, too. Although I early found out, that the number of "1" is what counts, I first wanted to fabricate help functions for the conditions no"1", one"1" and two"1". But I miserably failed, because, whatever I tried, I always needed three damned inverters for doing this. Only when I tried to count the "1" in a binary counter and to use the two digits of this counter as help functions, I was happy to see, how simple the realisation was and that only two inverters were needed. So, you see, I was in luck... Kai |
| Topic | Author | Date |
| weekend brainteaser | 01/01/70 00:00 | |
| here goes my weekend. | 01/01/70 00:00 | |
| Dont worry once you see the answer its obvious. | 01/01/70 00:00 | |
| Logically thinking... | 01/01/70 00:00 | |
| you are quite close | 01/01/70 00:00 | |
| One solution... | 01/01/70 00:00 | |
| yey we have a winner | 01/01/70 00:00 | |
| Very Nice | 01/01/70 00:00 | |
| Thanks | 01/01/70 00:00 | |
| An Alternate Solution | 01/01/70 00:00 | |
| Yes... | 01/01/70 00:00 | |
Ive run out ;-( | 01/01/70 00:00 | |
| Congratulations, Kai! | 01/01/70 00:00 | |
| Thanks | 01/01/70 00:00 | |
| Now it is clearer... | 01/01/70 00:00 |