??? 08/11/05 17:59 Read: times |
#99211 - Ok, let me try Responding to: ???'s previous message |
Switched Mode PSU ?
Of course, it is difficult to do 100A in a linear PS without frying eggs. Ok, let me try: There is a 4 bit weighing of each colour (this is for Steve, thus the 'u' in color) this constitutes not intensity but "weight". in other words, if the "weight" is 3 (0011) the particular colour will get 3/16 of the intensity. Each LED is controlled by a constant current generator with an I matching full intensity. So, to achieve a colour the 3 colors are loaded with the corresponding "weight" (e.g. 0 blue, 7 green and 8 red for yellow or 0 blue, 0 green, 15 red for red). one method would be to run 16 pulses on a separate pin (all chips in parallel) this way pulse# weight weight weight weight (binary) 8 4 2 1 0000 off off off off 0001 off off off on 0010 off off on off 0011 off off on off 0100 off on off off 0101 off on off off 0110 off on off off 0111 off on off off 1000 on off off off 1001 on off off off 1010 on off off off 1011 on off off off 1100 on off off off 1101 on off off off 1110 on off off off 1111 on off off off The "0000 nothing on" is not a mistake, it is the time in which ambient light is measured. One method The overall intensity would be controlled by e.g sending 16 pulses every 8 milliseconds, if it took 8ms to send the pulses there would be full intensity of the entire sign, if it took 4ms the intensity of the entire sign would be half. This is one possible way to do it, others may be used. Erik |
Topic | Author | Date |
soliciting input for LED chip | 01/01/70 00:00 | |
Application | 01/01/70 00:00 | |
spi | 01/01/70 00:00 | |
the constant current circuit can not be | 01/01/70 00:00 | |
Switch mode ? | 01/01/70 00:00 | |
Ok, let me try | 01/01/70 00:00 | |
Photodiode | 01/01/70 00:00 | |
nah | 01/01/70 00:00 | |
resistor and current | 01/01/70 00:00 | |
words | 01/01/70 00:00 | |
I am and I will | 01/01/70 00:00 |