??? 12/14/07 06:41 Read: times Msg Score: +1 +1 Informative |
#148192 - CUte circuit - does NOT work levels above 8 volts Responding to: ???'s previous message |
The reverse breakdown voltage of the BE junction of a transistor is usually somewhere near 5 volts. It never goes to 10 volts - maybe in some very special cases.
This makes this circuit unusable above 8 volt logic "levels". I also suspect it will give a huge overshoot into the 3 volt circuitry on the rising edge of the 5 volt side. In the worst case it will bite the circuitry in there. Bipolar transistors are also performing badly when driven to saturation. Looks like they have mentioned that in the article but this also affects a bundle of parameters which in turn cause instability etc. I think someone mentioned this already. Bidirectional level shifting - I personally avoid it if possible. It is a very complex thing to do even with readily available circuits and the complexity is not the number of pins it is the initialization and especially the circumstances BEFORE initialization has taken place. |
Topic | Author | Date |
Bidirectional level translation with transistors | 01/01/70 00:00 | |
why use discretes whern a cheap chip exist. | 01/01/70 00:00 | |
~0.3us worst case | 01/01/70 00:00 | |
74LVC4245 is not "automatically" bidir... | 01/01/70 00:00 | |
74LVC4245 has 24 leads | 01/01/70 00:00 | |
no overkill | 01/01/70 00:00 | |
none of these are bidir | 01/01/70 00:00 | |
24 leads | 01/01/70 00:00 | |
and what? | 01/01/70 00:00 | |
What! | 01/01/70 00:00 | |
but the 24 pins don't provide equivalent... | 01/01/70 00:00 | |
Still less :) | 01/01/70 00:00 | |
No steep egdes! | 01/01/70 00:00 | |
time to get rid of that superfast logic, Kai :-) | 01/01/70 00:00 | |
CUte circuit - does NOT work levels above 8 volts | 01/01/70 00:00 | |
There Are Proper Circuits for This | 01/01/70 00:00 | |
A detailed analysis of this technique can be ... | 01/01/70 00:00 | |
Do I need to say more :) | 01/01/70 00:00 |