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???
04/30/07 14:06
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#138289 - C99 says
Responding to: ???'s previous message
C99 6.7.2.2 said:
Each enumerated type shall be compatible with char, a signed integer type, or an unsigned integer type. The choice of type is implementation-defined, but shall be capable of representing the values of all the members of the enumeration.


What would you expect from a language which does not know what is an integer?

JW (the C-hater)


List of 15 messages in thread
TopicAuthorDate
Quick C enumerated types question            01/01/70 00:00      
   Not to worry i've found out anyway.            01/01/70 00:00      
      What's a "quick C"            01/01/70 00:00      
   The answer was.....            01/01/70 00:00      
      not really            01/01/70 00:00      
         as has been discussed before            01/01/70 00:00      
            of course not            01/01/70 00:00      
         Not true            01/01/70 00:00      
   C99 says            01/01/70 00:00      
      more details            01/01/70 00:00      
      OK            01/01/70 00:00      
         not any more            01/01/70 00:00      
         In C99            01/01/70 00:00      
            Enumeration type vs. constant            01/01/70 00:00      
               Thanks for that everyone            01/01/70 00:00      

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