??? 03/18/07 21:10 Read: times |
#135219 - Moments of inertia. Responding to: ???'s previous message |
Mehdi said:
So in the torque-speed curve of motor when speed is 2666 pps for a 0.9 degree motor the torque must be at least 37.5 Ncm i did some try and i reached to this speed with 150 numbers of speed profile look up table (desired acceleration,deceleration and fix speed) but my load was only 50 gram Mehdi. Weight is NOT the issue, its moment of inertia - the resistance of an object to being TURNED. In rotational terms, torque = J dw/dt, where J is the moment of inertia and w is angular velocity, so dw/dt is angular acceleration. You NEED to know the moment of inertia, if the load is a flat disc, its easy, its (mass x r^2)/2 Steve |
Topic | Author | Date |
What is the best motor choice? | 01/01/70 00:00 | |
Motor | 01/01/70 00:00 | |
The Load is so heavy in this case | 01/01/70 00:00 | |
Moments of inertia. | 01/01/70 00:00 | |
Newton's second law | 01/01/70 00:00 | |
MI | 01/01/70 00:00 | |
Nice rendition of physics 101, first week... | 01/01/70 00:00 | |
uh...I mean... | 01/01/70 00:00 | |
Actually, you can do it yourself... | 01/01/70 00:00 |