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???
12/14/06 15:01
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 		 #129462 - Interpret it in binary
Responding to: ???'s previous message
Save This Code
255 -> 11111111b   (no zeros)
127 -> 01111111b   (one zero)
191 -> 10111111b
223 -> 11011111b
239 -> 11101111b
247 -> 11110111b
251 -> 11111011b
253 -> 11111101b
254 -> 11111110b
63  -> 00111111b   (two zeros)
95  -> 01011111b
111 -> 01101111b
119 -> 01110111b
123 -> 01111011b
125 -> 01111101b
126 -> 01111110b
159 -> 10011111b
...


List of 40 messages in thread
TopicAuthorDate
Looking for an algorithm.            01/01/70 00:00      
   I'd split it in two (or 4)            01/01/70 00:00      
      I've shown, in increseing detail, how to do it            01/01/70 00:00      
   Sorted, or only counted?            01/01/70 00:00      
      Counting is enough            01/01/70 00:00      
         Not sorting or counting then??            01/01/70 00:00      
            My approach.            01/01/70 00:00      
               Erik's idea is fast and simple!            01/01/70 00:00      
   did you even consider what I posted            01/01/70 00:00      
      I considered lookup tables.            01/01/70 00:00      
         look at my code it is right there            01/01/70 00:00      
         Can you explain your table?            01/01/70 00:00      
            Interpret it in binary            01/01/70 00:00      
               Hhm...            01/01/70 00:00      
                  Use of the table/algorithm            01/01/70 00:00      
                  misunderstanding            01/01/70 00:00      
                     Ah. I thought so.            01/01/70 00:00      
            explanation of table            01/01/70 00:00      
   table lookup            01/01/70 00:00      
   now, I'm confused            01/01/70 00:00      
      The keyword is "enumerate".            01/01/70 00:00      
         i give up since nobody can answer in english            01/01/70 00:00      
            Meaning #1            01/01/70 00:00      
               there must be some language problem here            01/01/70 00:00      
                  Basically, a)            01/01/70 00:00      
                     then this will work (and I believe the fastest)            01/01/70 00:00      
                        maybe yes            01/01/70 00:00      
                           maybe faster, but not6 what he ned            01/01/70 00:00      
                              it's sometimes not easy to describe what one needs            01/01/70 00:00      
                                 Sorting or counting            01/01/70 00:00      
                                    Bit shifting            01/01/70 00:00      
                                    I elaborated.            01/01/70 00:00      
                                       Christoph, have you tried...            01/01/70 00:00      
                                          It looks interesting ..            01/01/70 00:00      
                                             well, you said that...            01/01/70 00:00      
                                                here you are            01/01/70 00:00      
                                                   Works.            01/01/70 00:00      
                                                      compiler            01/01/70 00:00      
                                                         Benchmark            01/01/70 00:00      
                                                            thanks!            01/01/70 00:00      

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