??? 03/26/06 07:49 Read: times Msg Score: +1 +1 Good Answer/Helpful |
#113125 - Try using a PNP Responding to: ???'s previous message |
If you use a PNP transistor with the emitter going to VCC, things might start to work in your favour. In this instance, the base circuit will need to fall below VCC in order for the transistor to turn on. You might wish to add a resistor between the base and the emitter(VCC) to turn the transistor off. Start with a value of around 1K at a guess. The problem with using a NPN as per your circuit is that the base voltage would need to rise above VCC in order for it to turn on. |
Topic | Author | Date |
Switching an IC off using BJT? | 01/01/70 00:00 | |
Try using a PNP | 01/01/70 00:00 | |
Good Good | 01/01/70 00:00 | |
"expensive" is relative | 01/01/70 00:00 | |
Of course | 01/01/70 00:00 | |
Using a MOSFET makes sense | 01/01/70 00:00 | |
Good Info | 01/01/70 00:00 |