??? 04/01/10 14:58 Read: times |
#174754 - you're not? Responding to: ???'s previous message |
Andy Peters said:
The timer value is read into the two bytes (two MOVs essentially) and then the offset is added to the 16-bit word, then the two bytes are written back to the timer (two more MOVs).
Keil is big-endian. SDCC is little-endian. I'm not using the union. You're not? Then who/what is? Ah, you think if the code I write doesn't use it, noone uses it. Well those two moves in and out of the timer surely use it. And are they aware of endianness? |