??? 04/19/09 19:10 Read: times |
#164726 - Considerations Responding to: ???'s previous message |
First:
The equation I gave for power factor calculation does not calculate cos. Second: You can not divide a instant power value for an average apparent value. If the site time allows I wil prove the equation. V=v.sinwt I=I.sin(wt-teta) p=v.i=V.I.sinwt.sin(wt-teta) or p=V.I.sinwt[sinwt.cos(teta)-sin(teta).coswt] after simplify p=(V.I/2).[cos(teta)-cos(2wt).cos(teta)-sin(2wt).sin(teta)] After integrating for half a period cos(2wt) and sin(2wt) will be zero! So you will have the equation I gave. |
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Considerations | 01/01/70 00:00 | |
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