??? 04/19/09 11:12 Read: times |
#164721 - Real power devided by the apparent power Responding to: ???'s previous message |
Leon Suek said:
Hi,
.... I have voltage and current working and is accurately displaying on my LCD to the 1000th place. .... Also, if anyone has an alternative to what I am doing, please let me know, I am willing to learn from you! Instantaneous volt multiplied by the Instantaneous current will give you the real power, usually expressed in watts or kilowatts. Average or rms volt multiplied by the average or rms current will give you the apparent power, usually expressed in Volt Amps or Va or Kva. Real power divided by the apparent power will give you the power factor. John. |
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Cross-posting | 01/01/70 00:00 | |
occur about this time each year | 01/01/70 00:00 | |
power factor calculation | 01/01/70 00:00 | |
Seems complicated. | 01/01/70 00:00 | |
Real power devided by the apparent power | 01/01/70 00:00 | |
Considerations | 01/01/70 00:00 | |
Don't just think linear loads | 01/01/70 00:00 | |
kVA | 01/01/70 00:00 | |
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PF | 01/01/70 00:00 | |
Not too high loads | 01/01/70 00:00 | |
Considerations II | 01/01/70 00:00 | |
rms on wikipedia and my previous link | 01/01/70 00:00 | |
PF![]() | 01/01/70 00:00 |