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???
04/19/06 15:32
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#114537 - Question and answer
Responding to: ???'s previous message
Richared said:
At first, there's no current flow, so the rate at which the integrator is charging is constant (zero). You start charging the integrator when the first contact is made, and wait until the rate of charge is constant. It seems to me that this will apply to both normally open, and normally closed cases. Further, it seems quite unimportant whether it is of a given value, so long as it is constant. There's a "gotcha" in this method, however, and that's that the bounce interval will consist of a number of small intervals during which the rate is essentially constant, and it is up to the integrator to "smooth" these steps into a slope. If you can detect the transition between the resulting slope to a constant level, you're home. The crux, therefore, is to select a time constant which will make it apparent that the charge rate is constant.

But doesn't mean this, that you have to sample the output of integrator during the whole bouncing event plus an extra time and that you have to analyze the samples in order to interpret the slopes by a suited algorithm? Isn't this much more sophisticated than "my" methode of only looking for the last toggling?

Richard said:
I'm curious about one thing, and that's the 0.2 ms value that was introduced in a previous post. I think that the last time I looked at reed relay spec's, the transition time, from open to closed, was on the order of 2 ms. The debounce time that was most frequently used, IIRC, was aobut 20 ms. Have reed relays improved that much in the last decade?

http://www.cotorelay.com/html/reed...series.htm

Only what I found first when googling for "reed relay"...

Kai

List of 52 messages in thread
TopicAuthorDate
Measuring Bounce of a Reed Switch            01/01/70 00:00      
   Current progress.            01/01/70 00:00      
      reply            01/01/70 00:00      
         DSO            01/01/70 00:00      
            Of course its a good idea ;-)            01/01/70 00:00      
               also..            01/01/70 00:00      
                  Rather redrawing, i prefer ...            01/01/70 00:00      
   Schematic is incomplete            01/01/70 00:00      
      Simple way            01/01/70 00:00      
   I would do it like that            01/01/70 00:00      
      detecting end of bounce?            01/01/70 00:00      
         Much simpler            01/01/70 00:00      
            this is all getting complicated            01/01/70 00:00      
               there may be definition problem here            01/01/70 00:00      
                  Thanks Richard            01/01/70 00:00      
                  Question and answer            01/01/70 00:00      
                     You're right, of course            01/01/70 00:00      
                        They tell it here            01/01/70 00:00      
                           Yes, it's pretty complete.            01/01/70 00:00      
                              Form A            01/01/70 00:00      
                     More sophisticated? Maybe not.            01/01/70 00:00      
                        OK brass tacks            01/01/70 00:00      
                           that's the basic idea            01/01/70 00:00      
                              60386 processor            01/01/70 00:00      
                                 that wasn't the point, Suresh            01/01/70 00:00      
                                    resolution/max error using ralph            01/01/70 00:00      
                                       not so fast ...            01/01/70 00:00      
                                    reply            01/01/70 00:00      
                                       Really?            01/01/70 00:00      
                                          I doubted when i typed            01/01/70 00:00      
                                             and the manual is right! sorry.            01/01/70 00:00      
                                                Really?            01/01/70 00:00      
                                                   correction            01/01/70 00:00      
                                                      There could be. But I made the mistake            01/01/70 00:00      
            Quantum flux compensator?            01/01/70 00:00      
               is it still April 1            01/01/70 00:00      
                  You are right but,            01/01/70 00:00      
               he means a flux capacitor ...            01/01/70 00:00      
                  And I thought...            01/01/70 00:00      
                  Compensator            01/01/70 00:00      
                     Translation            01/01/70 00:00      
            quantum flux capacitor?            01/01/70 00:00      
               language, culture            01/01/70 00:00      
                  reply : april 1!            01/01/70 00:00      
                     no, it was a natural response            01/01/70 00:00      
                        Ok Erik.            01/01/70 00:00      
                           The "Flux Capacitor" is from a movie            01/01/70 00:00      
                              Yes. to some extent!            01/01/70 00:00      
                     Never wanted to fool you!            01/01/70 00:00      
                        Obviously            01/01/70 00:00      
                           A joke and fooling someone is NOT the sa            01/01/70 00:00      
                              This made me think like that            01/01/70 00:00      

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