| ??? 09/02/12 22:07 Read: times |
#188215 - Right back to real basics! Responding to: ???'s previous message |
Richard Erlacher said:
Perhaps a look at the "bible" would clarify some of what you ask. Links to the so-called "bible" for the 8051 are here; but I think it's even more basic than that - fundamental digital logic? "0xFF" is a "short-hand" way of writing the state of eight signals grouped together as a "byte" or "octet". We write "0xFF" and "0xFE" (hexadecimal) because it's quicker & easier than writing the eight bits individually as "11111111" and "11111110" Sai Siddharth said:
1) Does this mean the equivalent of 1 is 0xFF? No: '1' is a single bit; 0xFF is (at least) 8 bits - all at '1' 2) Does 0xFF mean the port is currently HIGH? On an 8051, a Port contains 8 bits, each of which can, independently, be high (1) or low (0) - so it is meaningless to speak of the Port being "high" or "low". |
| Topic | Author | Date |
| Does 0xFF refer to HIGH? Simple blink program | 01/01/70 00:00 | |
| Now ... I haven't examined your code ... | 01/01/70 00:00 | |
| Right back to real basics! | 01/01/70 00:00 | |
You are nearly there  | 01/01/70 00:00 |