Well did a bit of searching there, found a good post saying it is impossible to convert Binary straight to ASCII. You must go to BCD or hex first. Basically he said go convert to bcd, then add 30 to every group. So if i wanted the ascii digit one, i would send 31.. etc.
This is some code i found to convert to bcd:

BIN_DEC: MOV A,R0
MOV B,#100
DIV AB
MOV R3,A ; R3 CONTAIN HUNDRED NUMBER
MOV A,B
MOV B,#10
DIV AB
MOV R2,A ; R2 CONTAIN TENTH NUMBER
MOV R1,B ; R1 CONTAIN LEFT DECIMAL NUMBER
LJMP BCD_ASCII
RET


BCD_ASCII:
MOV A, R0
ADD A, #30
MOV A, R1
ADD A, #30
MOV A, R2
ADD A, #30

Questions:
Would this code work okay?
How would i show the right side decimal number?
Should i use a subroutine to add 30?

NB My knowledge of assembly code is very low.